Educreations log in
Author: i | 2025-04-24
Describes how to log in to Educreations for the first time or as a returning student. Also covers how to access courses.
Log in to Educreations - YouTube
Log 4 – (log 3 – log 4)= log 3 – log 5 + log 5 – log 4 – log 3 + log 4= 0(ii) 3x+y-z3x+y-z = 30= 1Question 9. If x = log10 12, y = log4 2 × log10 9 and z = log10 0.4, find the values of(i) x – y – z(ii) 7x-y-zAnswer:Given:x = log10 12y = log4 2 × log10 9z = log10 0.4(i) x – y – zLet us substitute the given values, we getx – y – z = log10 12 – log4 2 × log10 9 – log10 0.4= log10 (3×4) – log4 41/2 × log10 32 – log10 4/10= log10 3 + log10 4 – ½ log4 4 × 2 log10 3 – (log10 4 – log10 10)= log10 3 + log10 4 – ½ × 1 × 2 log10 3 – log10 4 + 1= log10 3 + log10 4 – log10 3 – log10 4 + 1= 1(ii) 7x-y-z7x-y-z = 71= 7Question 10. If log V + log 3 = log π + log 4 + 3 log r, find V in terms of other quantities.Answer:Given:log V + log 3 = log π + log 4 + 3 log rLet us simplify the given expression to find V,log (V × 3) = log (π × 4 × r3)log 3V = log 4πr33V = 4πr3V = 4πr3/3Question 11. Given 3 (log 5 – log 3) – (log 5 – 2 log 6) = 2 – log n, find n.Answer:Given:3 (log 5 – log 3) – (log 5 – 2 log 6) = 2 – log nLet us simplify the given expression to find n,3 log 5 – 3 log 3 – log 5 + 2 log 6 = 2 – log n2 log 5 – 3 log 3 + 2 log 6 = 2 (1) – log nlog 52 – log 33 + log 62 = 2 log 10 – log n [Since, 1 = log 10]log 25 – log 27 + log 36 – log 102 = – log nlog n = – log 25 + log 27 – log 36 + log 100= (log 100 + log 27) – (log 25 + log 36)= log (100×27) – log (25×36)= log (100×27)/(25×36)log n = log 3n = 3Question 12. Given that log10 y + 2 log10 x = 2, express y in terms of x.Answer:Given:log10 y + 2 log10 x = 2Let us simplify the given expression,log10 y + log10 x2 = 2(1)log10 y + log10 x2 = 2 log10 10log10 (y×x2) = log10 102yx2 = 100y = 100/x2Question 13. Express log10 2 + 1 in the form log10x.Answer:Given:log10 2 + 1Let us simplify the given expression,log10 2 + 1 = log10 2 + log10 10 [Since, 1 = log10 10 ]= log10 (2×10)= log10 20Question 14. If a2 = log10 x, b2 = log10 y and a2/2 – b2/3 = log10 z. Express z in terms of x and y.Answer:Given:a2 = log10 xb2 = log10 ya2/2 – Describes how to log in to Educreations for the first time or as a returning student. Also covers how to access courses. B2/3 = log10 zLet us substitute the given values in the expression, we getlog10 x/2 – log10 y/3 = log10 zlog10 x1/2 – log10 y1/3 = log10 zlog10 √x – log10 ∛y = log10 zlog10 √x/∛y = log10 z√x/∛y = zz = √x/∛yQuestion 15. Given that log m = x + y and log n = x – y, express the value of log m²n in terms of x and y.Answer:Given:log m = x + ylog n = x – ylog m²nLet us simplify the given expression,log m²n = log m2 + log n= 2 log m + log nBy substituting the given values, we get= 2 (x + y) + (x – y)= 2x + 2y + x – y= 3x + yQuestion 16. Given that log x = m + n and log y = m – n, express the value of log (10x/y2) in terms of m and n.Answer:Given:log x = m + nlog y = m – nlog (10x/y2)Let us simplify the given expression,log (10x/y2) = log 10x – log y2= log 10 + log x – 2 log y= 1 + log x – 2 log y= 1 + (m + n) – 2(m – n)= 1 + m + n – 2m + 2n= 1 – m + 3nQuestion 17. If log x/2 = log y/3, find the value of y4/x6.Answer:Given:log x/2 = log y/3Let us simplify the given expression,By cross multiplying, we get3 log x = 2 log ylog x3 = log y2so, x3 = y2now square on both sides, we get(x3)2 = (y2)2x6 = y4y4/x6 = 1Question 18. Solve for x:(i) log x + log 5 = 2 log 3(ii) log3 x – log3 2 = 1(iii) x = log 125/log 25(iv) (log 8/log 2) × (log 3/log√3) = 2 log xAnswer:(i) log x + log 5 = 2 log 3Let us solve for x,Log x = 2 log 3 – log 5= log 32 – log 5= log 9 – log 5= log (9/5)∴ x = 9/5(ii) log3 x – log3 2 = 1Let us solve for x,log3 x = 1 + log3 2= log3 3 + log3 2 [Since, 1 can be written as log3 3 = 1]= log3 (3×2)= log3 6∴ x = 6(iii) x = log 125/log 25x = log 53/log52= 3 log 5/ 2 log 5= 3/2 [Since, log 5/log 5 = 1]∴ x = 3/2(iv) (log 8/log 2) × (log 3/log√3) = 2 log x(log 23/log 2) × (log 3/log31/2) = 2 log x(3log 2/log 2) × (log 3/½ log 3) = 2 log x3 × 1/(½) = 2 log x3 × 2 = 2 log x6 = 2 log xlog x = 6/2log x = 3x = (10)3= 1000∴ x = 1000Question 19. Given 2 log10 x + 1= log10 250, find(i) x(ii) log102xAnswer:Given:2 log10 x + 1= log10 250(i) let us simplify the above expression,log10 x2 + log10 10 = log10 250 [Since, 1 can be written as log10 10]log10 (x2 × 10) =Comments
Log 4 – (log 3 – log 4)= log 3 – log 5 + log 5 – log 4 – log 3 + log 4= 0(ii) 3x+y-z3x+y-z = 30= 1Question 9. If x = log10 12, y = log4 2 × log10 9 and z = log10 0.4, find the values of(i) x – y – z(ii) 7x-y-zAnswer:Given:x = log10 12y = log4 2 × log10 9z = log10 0.4(i) x – y – zLet us substitute the given values, we getx – y – z = log10 12 – log4 2 × log10 9 – log10 0.4= log10 (3×4) – log4 41/2 × log10 32 – log10 4/10= log10 3 + log10 4 – ½ log4 4 × 2 log10 3 – (log10 4 – log10 10)= log10 3 + log10 4 – ½ × 1 × 2 log10 3 – log10 4 + 1= log10 3 + log10 4 – log10 3 – log10 4 + 1= 1(ii) 7x-y-z7x-y-z = 71= 7Question 10. If log V + log 3 = log π + log 4 + 3 log r, find V in terms of other quantities.Answer:Given:log V + log 3 = log π + log 4 + 3 log rLet us simplify the given expression to find V,log (V × 3) = log (π × 4 × r3)log 3V = log 4πr33V = 4πr3V = 4πr3/3Question 11. Given 3 (log 5 – log 3) – (log 5 – 2 log 6) = 2 – log n, find n.Answer:Given:3 (log 5 – log 3) – (log 5 – 2 log 6) = 2 – log nLet us simplify the given expression to find n,3 log 5 – 3 log 3 – log 5 + 2 log 6 = 2 – log n2 log 5 – 3 log 3 + 2 log 6 = 2 (1) – log nlog 52 – log 33 + log 62 = 2 log 10 – log n [Since, 1 = log 10]log 25 – log 27 + log 36 – log 102 = – log nlog n = – log 25 + log 27 – log 36 + log 100= (log 100 + log 27) – (log 25 + log 36)= log (100×27) – log (25×36)= log (100×27)/(25×36)log n = log 3n = 3Question 12. Given that log10 y + 2 log10 x = 2, express y in terms of x.Answer:Given:log10 y + 2 log10 x = 2Let us simplify the given expression,log10 y + log10 x2 = 2(1)log10 y + log10 x2 = 2 log10 10log10 (y×x2) = log10 102yx2 = 100y = 100/x2Question 13. Express log10 2 + 1 in the form log10x.Answer:Given:log10 2 + 1Let us simplify the given expression,log10 2 + 1 = log10 2 + log10 10 [Since, 1 = log10 10 ]= log10 (2×10)= log10 20Question 14. If a2 = log10 x, b2 = log10 y and a2/2 – b2/3 = log10 z. Express z in terms of x and y.Answer:Given:a2 = log10 xb2 = log10 ya2/2 –
2025-03-25B2/3 = log10 zLet us substitute the given values in the expression, we getlog10 x/2 – log10 y/3 = log10 zlog10 x1/2 – log10 y1/3 = log10 zlog10 √x – log10 ∛y = log10 zlog10 √x/∛y = log10 z√x/∛y = zz = √x/∛yQuestion 15. Given that log m = x + y and log n = x – y, express the value of log m²n in terms of x and y.Answer:Given:log m = x + ylog n = x – ylog m²nLet us simplify the given expression,log m²n = log m2 + log n= 2 log m + log nBy substituting the given values, we get= 2 (x + y) + (x – y)= 2x + 2y + x – y= 3x + yQuestion 16. Given that log x = m + n and log y = m – n, express the value of log (10x/y2) in terms of m and n.Answer:Given:log x = m + nlog y = m – nlog (10x/y2)Let us simplify the given expression,log (10x/y2) = log 10x – log y2= log 10 + log x – 2 log y= 1 + log x – 2 log y= 1 + (m + n) – 2(m – n)= 1 + m + n – 2m + 2n= 1 – m + 3nQuestion 17. If log x/2 = log y/3, find the value of y4/x6.Answer:Given:log x/2 = log y/3Let us simplify the given expression,By cross multiplying, we get3 log x = 2 log ylog x3 = log y2so, x3 = y2now square on both sides, we get(x3)2 = (y2)2x6 = y4y4/x6 = 1Question 18. Solve for x:(i) log x + log 5 = 2 log 3(ii) log3 x – log3 2 = 1(iii) x = log 125/log 25(iv) (log 8/log 2) × (log 3/log√3) = 2 log xAnswer:(i) log x + log 5 = 2 log 3Let us solve for x,Log x = 2 log 3 – log 5= log 32 – log 5= log 9 – log 5= log (9/5)∴ x = 9/5(ii) log3 x – log3 2 = 1Let us solve for x,log3 x = 1 + log3 2= log3 3 + log3 2 [Since, 1 can be written as log3 3 = 1]= log3 (3×2)= log3 6∴ x = 6(iii) x = log 125/log 25x = log 53/log52= 3 log 5/ 2 log 5= 3/2 [Since, log 5/log 5 = 1]∴ x = 3/2(iv) (log 8/log 2) × (log 3/log√3) = 2 log x(log 23/log 2) × (log 3/log31/2) = 2 log x(3log 2/log 2) × (log 3/½ log 3) = 2 log x3 × 1/(½) = 2 log x3 × 2 = 2 log x6 = 2 log xlog x = 6/2log x = 3x = (10)3= 1000∴ x = 1000Question 19. Given 2 log10 x + 1= log10 250, find(i) x(ii) log102xAnswer:Given:2 log10 x + 1= log10 250(i) let us simplify the above expression,log10 x2 + log10 10 = log10 250 [Since, 1 can be written as log10 10]log10 (x2 × 10) =
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2025-04-03Including log archiving. Select Events to Log - Events Tab Connection Requests Log events related to connection requests. System Status Log events related to changes in system status. Rewrite Log events related to rewrite policies. System Errors Log events related to system errors. Statistics Log user access statistics reported on the System > Log/Monitoring > Statistics tab. If you unselect the Statistics option, the statistics are not written to the log file, but are still reported on the statistics page. Performance Log events related to SiteMinder. License Protocol Events Log events related to licensing. Reverse Proxy Logs events related to reverse proxy information. Select Events to Log - User Access Tab Login/logout Log events related to sign in and sign out. SAM/Java Log events related to user access to SAM/Java in the local log file. User Settings Log events related to changes to user settings in the local log file. Meeting Events Log events related to meeting information. Client Certificate Log events related to certificate security. IF-MAP Client User Messages Log events related to IF-MAP. Pulse Client Messages Log events related to Pulse clients. HTML5 Access Log events related to HTML5 access. Web Requests Log events related to user access to web. File Requests Log events related to user access to files. Meeting Log events related to user access to meetings. Secure Terminal Log events related to user access to secure terminal. VPN Tunneling Log events related to user access to VPN tunneling. SAML Log events related to user access
2025-04-07