Pulse 1

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New types of analog pulse oscillators: Pulse 1/2, Pulse 2/5, Pulse 1/3, Pulse 1/4, Pulse 1/5, Pulse 1/6, Pulse 1/8. New types of analog oscillators with inverted phase: Saw

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PG911 and PG914 Integral 50 Ω SMA(f) Step Recovery Diode outputs Dual 2.5 to 6 V variable amplitude outputs ±1 ns in 1 ps steps timing deskew 200 ns to 4 μs pulse width 1 μs to 1 s internal clock period ​ –20 dB 10 GHz SMA(m-f) attenuator included with Step Recovery Diode outputsPG912 and PG914 External 50 Ω N(m) positive and negative Tunnel Diode pulse heads Dual > 200 mV fixed amplitude outputs ​±200 ps in 1 ps steps timing deskew Inter-series N(f) – SMA(m) adapter included with Tunnel Diode pulse headsThe fast-transition pulse can stimulate a transmission path, device or network with a broad spectrum signal in a single instant. Such a pulse is very useful for many of the high-speed broadband measurements that we need to make; for instance in time-domain reflectometry, semiconductor test, gigabit interconnect and port test and in radar.Differential high-speed data in particular dominates the measurement challenge in our digital, computing, interconnect and telecommunications systems. Surprisingly, cost-effective fast-transition differential pulse generators have been very hard to find ... until now!Typical applications include: TDR/TDT network and match analysis Spectral and flatness measurements Timing, jitter and crosstalk determinationsThe PG900 Pulse Generators can partner the PicoScope 9300 20 GHz Sampling Oscilloscope in many of these applications. Hardware New types of analog pulse oscillators: Pulse 1/2, Pulse 2/5, Pulse 1/3, Pulse 1/4, Pulse 1/5, Pulse 1/6, Pulse 1/8. New types of analog oscillators with inverted phase: Saw Electra Gladiator Nemesis Saurus Warlock RayBlaster Overview Comparison Bundles Sounds. Electra Icarus Pulse 1/2, Pulse 2/5, Pulse 1/3, Pulse 1/4, Pulse 1/5, Pulse 1/6, Pulse 1/8. The pulses is about the same (short + long == long + short), and that 1/4 of that entire interval is equal to a short pulse, and 3/4 of that entire interval is equal to a long pulse. Hopefully this makes sense.Based on our label track, the time between the starts of the second and third pulses is 0.001565 - 0.000794 = 0.000771 seconds, or 771 µs. 771 / 4 = 192.75, so based on that, a short pulse is about 192 µs and a long pulse about 578 µs. Hint: Mac keyboard shortcut for µ is command mOf course I assume the average of all the differences in times would be more accurate than a single one, so I whipped up a quick python script to figure that out for me:#! /usr/bin/env python3from statistics import meaninfile = '/Users/n8henrie/Desktop/RF_Arduino_Post/Label Track.txt'with open(infile) as f: cols = [float(col[0].strip()) for col in [line.split('\t') for line in f.readlines()]]diffs = []for i in range(len(cols) - 1): diffs.append(cols[i + 1] - cols[i])avg=mean(diffs) * 10**6output_str = ( "Mean time between pulse starts: {avg:.5g} µs\n" "Average duration of long pulse: {long:.5g} µs\n" "Average duration of short pulse: {short:.5g} µs\n\n" "All pulses:\n{diffs}" .format(avg=avg, long=avg / 4 * 3, short=avg / 4, diffs=diffs) )print(output_str)And its output:Mean time between pulse starts: 762.96 µsAverage duration of long pulse: 572.22 µsAverage duration of short pulse: 190.74 µsAll pulses:[0.000794, 0.000771, 0.000748, 0.000771, 0.000771, 0.0007480000000000004, 0.0007599999999999994, 0.0007590000000000001, 0.000771, 0.0007369999999999998, 0.0007600000000000003, 0.0007939999999999996, 0.0007140000000000011, 0.0007819999999999997, 0.0007709999999999991, 0.0007600000000000003, 0.0007480000000000004, 0.0007709999999999991, 0.0007480000000000004, 0.0007830000000000007, 0.0007369999999999981, 0.0007710000000000009, 0.0007589999999999993, 0.0007830000000000024]However, this is all predicated on the assumption that there is a 3:1 ratio of the long to short intervals. Because of the possibility that it’s something close to 3:1 but not quite, I was uncomfortable just assuming that the pulse lengths were exactly 3:1. For that reason, I also wanted to show how you can also directly measure the interval lengths by zooming way in, highlighting a segment, displaying Length -> Samples down bottom, and doing some math.For example,Picking out a short pulseZooming inHighlighting — note the Project Rate of 384000 and Length of 73 samples down below73 samples at 384000 samples per second yields 190 µs durationThe measured short pulse duration is exactly what we had calculated based off the label track. Note where I started and stopped measuring — I figure I want to capture the signal from the moment it goes high to the instant it is turned off, which in my mind means from the time is starts increasing to the time it starts decreasing. Therefore, I chose to measure from the first sample that was clearly above baseline to the time it was clearly decreasing. It definitely helps expand the window vertically and zoom in.Repeat this process for the long pulses, and we find that we were very close:Finally, the last thing we need to do is measure the long pause after the last pulse in each set.5953 is about 31 short pulses, or a little over 7 “total cycle” durations (4 * short pulse).SummaryOkay, well that’s

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User6051

PG911 and PG914 Integral 50 Ω SMA(f) Step Recovery Diode outputs Dual 2.5 to 6 V variable amplitude outputs ±1 ns in 1 ps steps timing deskew 200 ns to 4 μs pulse width 1 μs to 1 s internal clock period ​ –20 dB 10 GHz SMA(m-f) attenuator included with Step Recovery Diode outputsPG912 and PG914 External 50 Ω N(m) positive and negative Tunnel Diode pulse heads Dual > 200 mV fixed amplitude outputs ​±200 ps in 1 ps steps timing deskew Inter-series N(f) – SMA(m) adapter included with Tunnel Diode pulse headsThe fast-transition pulse can stimulate a transmission path, device or network with a broad spectrum signal in a single instant. Such a pulse is very useful for many of the high-speed broadband measurements that we need to make; for instance in time-domain reflectometry, semiconductor test, gigabit interconnect and port test and in radar.Differential high-speed data in particular dominates the measurement challenge in our digital, computing, interconnect and telecommunications systems. Surprisingly, cost-effective fast-transition differential pulse generators have been very hard to find ... until now!Typical applications include: TDR/TDT network and match analysis Spectral and flatness measurements Timing, jitter and crosstalk determinationsThe PG900 Pulse Generators can partner the PicoScope 9300 20 GHz Sampling Oscilloscope in many of these applications. Hardware

2025-04-06
User6190

The pulses is about the same (short + long == long + short), and that 1/4 of that entire interval is equal to a short pulse, and 3/4 of that entire interval is equal to a long pulse. Hopefully this makes sense.Based on our label track, the time between the starts of the second and third pulses is 0.001565 - 0.000794 = 0.000771 seconds, or 771 µs. 771 / 4 = 192.75, so based on that, a short pulse is about 192 µs and a long pulse about 578 µs. Hint: Mac keyboard shortcut for µ is command mOf course I assume the average of all the differences in times would be more accurate than a single one, so I whipped up a quick python script to figure that out for me:#! /usr/bin/env python3from statistics import meaninfile = '/Users/n8henrie/Desktop/RF_Arduino_Post/Label Track.txt'with open(infile) as f: cols = [float(col[0].strip()) for col in [line.split('\t') for line in f.readlines()]]diffs = []for i in range(len(cols) - 1): diffs.append(cols[i + 1] - cols[i])avg=mean(diffs) * 10**6output_str = ( "Mean time between pulse starts: {avg:.5g} µs\n" "Average duration of long pulse: {long:.5g} µs\n" "Average duration of short pulse: {short:.5g} µs\n\n" "All pulses:\n{diffs}" .format(avg=avg, long=avg / 4 * 3, short=avg / 4, diffs=diffs) )print(output_str)And its output:Mean time between pulse starts: 762.96 µsAverage duration of long pulse: 572.22 µsAverage duration of short pulse: 190.74 µsAll pulses:[0.000794, 0.000771, 0.000748, 0.000771, 0.000771, 0.0007480000000000004, 0.0007599999999999994, 0.0007590000000000001, 0.000771, 0.0007369999999999998, 0.0007600000000000003, 0.0007939999999999996, 0.0007140000000000011, 0.0007819999999999997, 0.0007709999999999991, 0.0007600000000000003, 0.0007480000000000004, 0.0007709999999999991, 0.0007480000000000004, 0.0007830000000000007, 0.0007369999999999981, 0.0007710000000000009, 0.0007589999999999993, 0.0007830000000000024]However, this is all predicated on the assumption that there is a 3:1 ratio of the long to short intervals. Because of the possibility that it’s something close to 3:1 but not quite, I was uncomfortable just assuming that the pulse lengths were exactly 3:1. For that reason, I also wanted to show how you can also directly measure the interval lengths by zooming way in, highlighting a segment, displaying Length -> Samples down bottom, and doing some math.For example,Picking out a short pulseZooming inHighlighting — note the Project Rate of 384000 and Length of 73 samples down below73 samples at 384000 samples per second yields 190 µs durationThe measured short pulse duration is exactly what we had calculated based off the label track. Note where I started and stopped measuring — I figure I want to capture the signal from the moment it goes high to the instant it is turned off, which in my mind means from the time is starts increasing to the time it starts decreasing. Therefore, I chose to measure from the first sample that was clearly above baseline to the time it was clearly decreasing. It definitely helps expand the window vertically and zoom in.Repeat this process for the long pulses, and we find that we were very close:Finally, the last thing we need to do is measure the long pause after the last pulse in each set.5953 is about 31 short pulses, or a little over 7 “total cycle” durations (4 * short pulse).SummaryOkay, well that’s

2025-03-30
User8624

And s=−0.0012 THz) enables us to estimate 〈cosθ〉=−0.74, meaning that seven molecules are facing one side for every molecule facing the other side. According to a calculation performed under the same conditions using an evolutionary algorithm with an unrestricted parameterization of the phase, this value can further be increased to 〈cosθ〉=−0.84. As shown in Fig. 4g, the optimized laser field consists of two long and weak pulses before the main pulse that contain approximately half of the energy of the main pulse. The two pulses pre-orient the molecule before the main kick, similar to what was shown in ref. 20 for alignment. Consequently, an improved rephasing of the rotational wave packet at the full revival period is achieved. The orientation revival is accompanied by a strong revival of the alignment (〈cos2θ〉=0.82).Figure 4: Optimization of impulsive orientation.a,b, N2+ images recorded at a time delay of τ=20.1 ps after the interaction of NO molecules with a 300 μJ, 90 fs FTL pulse (a) and a shaped laser pulse where a sigmoidal phase mask has been applied (b). c, Intensity integration of the images (A, in black, and B, in red) along the x axis. d, Evolution of 1−|〈cosθ2D〉| without a pump pulse, with the FTL pulse and with the sigmoidal phase function that leads to the optimization of the orientation, for five consecutive experimental images. The sigmoidal phase function clearly improves the orientation of the molecules and increases |〈cosθ2D〉| to 0.5. e,f, Time-dependent evolution (black line and points) and theoretical evolution (red lines) of 〈cosθ2D〉 and 〈cos2θ2D〉 obtained from the images recorded using the sigmoidal phase mask. g, Comparison of an experimental cross-correlation of the optimized pump pulse with an FTL pulse (black points) and the calculated pulse profile when applying the sigmoidal phase mask (red line).Full size imageTo achieve 〈cosθ〉=−0.74 a d.c. electric field of 13 kV cm−1 and a shaped laser pulse reaching a peak intensity of ∼2×1013 W cm−2 were used. Calculations suggest that on increasing the d.c. field to 50 kV cm−1 and allowing for peak intensities (within the shaped laser pulse) up to 3×1013 W cm−2 (which

2025-04-17
User1786

A client has an axillary temperature of 102.6 F (39.2°C). Which clinical manifestations would the nurse anticipate? (Select all that apply.)a) respiratory rate 30/min b) headache c) hunger d) cold, clammy skin e) red or flushed skinStudents also studiedTextbook solutionsFlashcard setsStudy guidesPractice testsChemistry: The Central Science14th Edition•ISBN: 9780134414232Bruce Edward Bursten, Catherine J. Murphy, H. Eugene Lemay, Matthew E. Stoltzfus, Patrick Woodward, Theodore E. Brown7,778 solutionsFundamentals of Nursing9th Edition•ISBN: 9780323465557 (1 more)Amy Hall, Anne Griffin Perry, Patricia A Potter, Patricia Stockert915 solutionsA client has an axillary temperature of 102.6 F (39.2°C). Which clinical manifestations would the nurse anticipate? (Select all that apply.)a) respiratory rate 30/min b) headache c) hunger d) cold, clammy skin e) red or flushed skina) respiratory rate 30/minb) headachee) red or flushed skinThe nurse is caring for several client's on a telemetry unit. Which clients' pulse rates need to be assessed for 1 full minute? (Select all that apply.)a) clients with abnormally slow pulse rates b) clients with regular rhythms c) clients with irregular pulse rates d) clients recovering from anesthesia e) clients with fast pulse ratesa) clients with abnormally slow pulse ratesc) clients with irregular pulse ratese) clients with fast pulse ratesThe nurse is performing bilateral comparison of pulse sites for strength and quality instead of counting the beats per minute. Which pulse locations will the nurse palpate to gather this assessment data? Select all that apply.a) Femoral b) Dorsalis pedis c) Apical d) Popliteal e) Posterior tibiala) Femoralb) Dorsalis pedisd) Popliteale) Posterior tibialUpon entering a client's room, the nurse notes the client's pulse oximetry to be 86%. What is the priority nursing action?a) Perform a respiratory assessment. b) Document the finding. c) Apply supplemental oxygen d) Contact healthcare provider to report findings.a) Perform a respiratory assessment.The nurse has assessed a pulse deficit when taking the pulse of a client. What does this assessment indicate for the client? (Select all that apply.)a) The total volume of blood during ventricular contraction b) The difference between apical and peripheral pulse rate c) The pulse pressure created when there is friction between the blood and the vessel walls d) The

2025-03-30
User1892

Or communication program. Stopping Continuous Operation of Position Table When the motor is executing continuous operation of position table with Ezi-STEPⅡ Plus-E, stop executing position table by following methods. www.fastech.co.kr... Page 41 Number of pulses per revolution. Pulse per 0~15 The range of ‘Axis Max Speed’parameter is depend Revolution on this value. Teaching Function Teaching can be executed only by User Program(GUI). For more information, refer to 「User Manual – Position Table Function」. www.fastech.co.kr... Page 42: 8. Other Operation Functions Input ‘PT Start’ number to execute speed control operation. For more information, refer to 「User Manual – Position Table Function」. Position Table Setting 【 】 Command High Accel. Decel. Wait Continuous JP Table Position type Speed Speed time time time Action 10000 2500 1000 5000 1500 -2500 1000 www.fastech.co.kr... Page 43: 8-2. Jog Operation Examples Jog - command Also, when any value except 0 is set to the ‘Jog Start Speed’ parameter, the relation between jog command and in-position is indicating as below diagram. Jog Speed Jog Moving pulse Jog Start speed Jog + command www.fastech.co.kr... Page 44: Origin Return (It is method for precise return to Z-pulse origin.)  When limit sensor is detected, stop by the stop method set in H / W Limit Stop Method (parameter No. 12, E-STOP / Stop) and then execute the remaining homing routine. www.fastech.co.kr... Page 45 ① : In case of position of sensor Dog is between the origin and +Limit Sensor ② : In case of position of sensor Dog is in the origin sensor ③ : In case of position of sensor Dog is between origin and -Limit Sensor www.fastech.co.kr... Page 46 It designates current mechanics position as origin irrespective sensor. 6) Z Phase (In case of Org Method = 5) ① : In case of Org Dir is 1 (CCW) ② : In case of Org Dir is 0 (CW) www.fastech.co.kr... Page 47: Stop Operation Pulse start position. [pulse] 1~ : pulse output repeatedly depends on setting.) Setting the pulse width. Pulse Width 1~1000[ms] The parameter range differs from the product version, listed as below. V06.01.2x.xx : -134,217,728 ~134,217,727(Start Position), 0 ~ 134,217,727(Pulse Period) www.fastech.co.kr... Page 48 The pulse is output only in bigger position area than ‘pulse starts Caution position ‘and is output in both motion directions. put Status Check By using DLL program, the user can check the trigger pulse output status. Refer to 「User Manual –

2025-04-10

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